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2x^2+80x+350=0
a = 2; b = 80; c = +350;
Δ = b2-4ac
Δ = 802-4·2·350
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-60}{2*2}=\frac{-140}{4} =-35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+60}{2*2}=\frac{-20}{4} =-5 $
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